If you connect a 12 V source through a 10 kΩ resistor divider with equal resistors, what is Vout?

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If you connect a 12 V source through a 10 kΩ resistor divider with equal resistors, what is Vout?

Two equal resistors in series across a supply split the voltage equally. With 12 V across two 10 kΩ resistors, the current is 12 V / (10 kΩ + 10 kΩ) = 0.6 mA. The drop across each resistor is I × R = 0.6 mA × 10 kΩ = 6 V. The midpoint, where Vout is taken, sits at 6 V above ground. This assumes nothing is loading the output; adding a load could shift the voltage if the load is not much larger than 10 kΩ.

Two equal resistors in series across a supply split the voltage equally. With 12 V across two 10 kΩ resistors, the current is 12 V / (10 kΩ + 10 kΩ) = 0.6 mA. The drop across each resistor is I × R = 0.6 mA × 10 kΩ = 6 V. The midpoint, where Vout is taken, sits at 6 V above ground. This assumes nothing is loading the output; adding a load could shift the voltage if the load is not much larger than 10 kΩ.

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